第一篇：2015年高一英语暑假作业答案(新人教版)
2015年高一英语暑假作业答案（新人教版）
第二部分 阅读理解(共两节，满分分)(共小题;每小题分，满分分)阅读下列短文，从每题所给的四个选项(A、B、C、和D)中，选出最佳选项，并在答题卡上将该项涂黑。
I was telling my boy Sonny the story of the hare and the tortoise.At the end I said, “ Son, remember: Be slow and steady, and that will win the race.Dont you think theres something to learn from the tortoise”
Sonny opened his eyes wide, “Do you mean next time when Im entering for the 60-metre race I should wish that Billy, Tony and Sandy would all fall asleep halfway”
I was shocked, “But the tortoise didnt wish that the hare would fall asleep!”
“He must have wished that,” Sonny said, “Otherwise how could he be so foolish as to race with the hareHe knew very well the hare ran a hundred times faster than he himself did.”
“He didnt have such a wish,” I insisted.“He won the race by perseverance, by pushing on steadily.” Sonny thought a while.“Thats a lie,” he said.“He won it because he was lucky.If the hare hadnt happened to fall asleep, the tortoise would never have won the race.He could be as steady as you like, or a hundred times steadier, but hed never have won the race.Thats for sure.”
I gave up.Todays children are not like what we used to be.Theyre just hopeless.1.The writer argued with his son because ______________.A.he liked tortoises while his son liked hares B.they disagreed about whether the tortoise was foolish C.he tried to teach his son a moral lesson but the son had totally different opinion D.he liked the story of the hare and the tortoise while his son didnt.2.Sonny believed that the tortoise ______________.A.won the race by his own hard working B.took a risk by agreeing to run a race C.was not given a fair chance in the race D.in fact did win the race luckily 3.Billy, Tony and Sandy must be_______________.A.boys who were unknown to Sonnys father B.boys who Sonny has run races with before C.boys who Sonny has never raced with before D.boys who Sonny did not expect to race with again 4.The writer thinks that his generation______________.A.are cleverer than Sonnys generation B.have the same ideas about life as Sonnys generation C.are more hopeful than Sonnys generation D.have different ideas about life from Sonnys generation 第二节(共5小题，每小题2分，满分10分)根据短文内容，从短文后的选项中选出能填入空白处的最佳选项，选项中有两项为多余选项。
Do you know AustraliaAustralia is the largest island in the world.It is a little smaller than China.It is in the south of the earth.1The population of Australia is nearly as large as that of Shanghai.2The cities in Australia have got little air or water pollution.The sky is blue and the water is clean.You can clearly see fish swimming in the rivers.Plants grow very well.Last month we visited Perth, the biggest city in western Australia, and went to a wild flowers exhibition.3We had a wonderful time.Perth is famous for its beautiful wild flowers.In spring every year Perth has the wild flowers exhibition.After visiting Perth, we spent the day in the countryside.We sat down and had a rest near a path at the foot of a hill.It was quiet and we enjoyed ourselves.Suddenly we heard bells ringing at the top of the hill.4There were about three hundred sheep coming towards us down the path.5After a short drive from any town, you will find yourself in the middle of white sheep.Sheep, sheep, everywhere are sheep.A.The government has made enough laws to fight pollution.B.Australia is the sixth largest country in the world.本文由为您提供供广大考生参考学习，希望对大家有所帮助，高中频道推荐。
第二篇：高一 英语暑假作业
Assignments for the Summer Vacation（假期作业）
2011-7
Listening（听力）:
Studio Classroom（空中英语教室）每天30分钟
Movies（电影）（带英文字幕）
Speaking（口语）:
Selected English Articles for Reading(朗读文章并录音)
Studio Classroom（空中英语教室）
Texts from our textbooks（课本中的课文）
Reading（阅读）:
Studio Classroom（空中英语教室）
21st Century（21世纪英文报）
Novels（小说）
Writing（写作）:
5 essays（5篇作文），包括:book reports（两篇读书报告）film reviews（两篇观影心得）
A diary or free writing（一篇日记或随笔）
Word bank: 2 words/ expressionsa day(25days)（单词积累；每日两词/词组，共25
天）
Handwriting（书法练习）
The works to be handed in（需上交的作业）
The Recording of your reading（文章录音）
5 essays(5篇作文)
Word bank(单词积累)
Handwriting（书法练习）
Writing portfolio.注意： 以上作业将计入下学期平时成绩。
开学考试内容：《空中英语》（50%）、及课本词汇（30%）、语法（20%）。
第三篇：高一英语暑假作业
高一英语暑假作业
一． 必做题
1.必修四单元形成性测试卷（六套）
2.《双语报》47期---51期（综合复习版、快乐阅读版）
3.自学预习必修五Moduole1（见提纲）
二． 选做题
1.甲+班：21st Century 暑假合刊、《快乐阅读》
2.甲班：21st Century 暑假合刊（初三版）、《快乐阅读》
第四篇：2015年高一英语暑假作业答案(合订本)
2015年高一英语暑假作业答案（合订本）
从A、B、C、D四个选项中，选出可以填入空白处的最佳选项。
1.I could _______ by the way she walked that her knee was still bothering her.A.separate B.tell C.find D.divide 2.______ in a well-known university is what everybody wishes for.A.Educated B.Being educated C.To educate D.Educating 3.His classmates offered him their congratulations ______ his successful performance.A.at B.on C.for D.of 4._______every member has arrived, lets set about _____ the plan for the next five years.A.Since;to work out B.Because;work out C.Now that;working out D.For;work out 5.Here are the first three books of his poem works, with the fourth one to _____ next month.A.come out B.publish C.replace D.work out 6.As he works in a remote area, he visits his parents only _______.A.anxiously B.occasionally C.urgently D.hopefully 7.His English is improving _______, which makes both his parents and his teacher happy.A.now and then B.little by little C.sooner or later D.one after another 8.It is surprising that such a young boy can swim ______ the river ______ 100 meters wide.A.over;measured B.across;measuring C.across;measures D.through;measuring 9.Li Ming is a student who is easy _____ though he has some trouble _____ his lessons.A.to be got along with;in B.to get along with;with C.to get along;in D.getting along with;with 10.I thought he would offer to pick me up._______, he even refused me when I asked him to do so.A.In other words B.Otherwise C.Whats more D.However 11.It suddenly ________ me how we could improve the situation.A.got B.struck C.beat D.occurred 12.Seeing the ______ sight, the girl was nearly _______ to death.A.terrifying;terrifying B.terrified;terrified C.terrifying;terrified D.terrified;terrifying 13._____ in a heavy snow, he didnt get there in time.A.Catching B.Catch C.Caught D.To catch 14.Dont blame yourself too much.Everyone has his ______ and weaknesses.A.powers B.strengths C.forces D.energies 15.The reason _____ he was late for the meeting was ____ he was held up by traffic jam during rush hours.A.why;because B.that;that C.why;that D.that;because 16.The child ______ in the countryside knows how to _____ animals like dogs, pigs and so on.A.raised;bring up B.brought up;raise C.fed;raise D.fed up;bring up 17.Scientists said that the winter of 2011 was _____ cold, and in fact it was much colder than predicted.A.frozen B.freezing C.freezingly D.froze 18.A local woman didnt _______ her tears when she saw her store destroyed by the fire.A.hold out B.hold back C.hold up D.hold on 19.The fact that she was foreign made ______ difficult for her to get a job in that country.A.this B.that C.her D.it 本文由为您提供供广大考生参考学习，希望对大家有所帮助，高中频道推荐。
第五篇：2018高一数学暑假作业答案（推荐）
2018高一数学暑假作业答案
：学习应该是一件轻松的活动。学习其实不用刻意去学习，它靠的是日积月累和逐渐的积淀。小编为大家分享高一数学暑假作业答案，希望能帮助同学们复习本门课程!
暑假作业(一)
一.选择题: D C A
二.填空题: 4.5.6.4.解: ,又，且a、b、c成等比数列，由余弦定理，得。，即。
5.解：。6.解: 由正弦定理及，得，即。，而。
。又，得。，即(当且仅当时=成立)。，即ABC的面积的最大值为。故填。
三.解答题:
7.解:(Ⅰ)由，得，由，得.所以.(Ⅱ)由正弦定理得.所以的面积
.8.解:(Ⅰ)由余弦定理及已知条件得，又因为的面积等于，所以，得.联立方程组解得，.(Ⅱ)由题意得，即，当时，，，当时，得，由正弦定理得，联立方程组解得，.所以的面积.9.解:∵sinA+cosA=cos(A-45)=，cos(A-45)=。又0
A=105.tanA=tan(45+60)=.SinA=sin105=sin(45+60)
=sin45cos60+cos45sin60=.S△ABC=ACAbsinA=23=。
解法二：∵sinA+cosA= ①,(sinA+cosA)2=.2sinAcosA=-.∵0
①-②，得cosA=。tanA=。(以下同解法一)
10.解:(1)依题意，,由正弦定理及
(2)由 由(舍去负值)
从而 由余弦定理，得
代入数值，得解得：
暑假作业(二)
一.选择题: B D B
3.解:在△ABC中，∵a, b, c成等差数列，2b=a+c.又由于B=30，S△ABC=acsinB
=acsin30=.ac=6.b2=a2+c2-2accosB=(a+c)2-2ac-2accosB=4b2-26-26cos30.解得b2=4+2=(1+)2.∵b为三角形的边，b0.b=1+.应选B.二.填空题: 4.5.6.4.解: ,。
5.解：由题意得:，两式相减，得.由的面积，得，所以.6.解:由得9+24sin(A+B)+16=37，又
当时，不等于6，故否定，.三.解答题:
7.解: 在△ABP中，APB=30BAP=120,由正弦定理知得.在△BPC中，又PBC=90，可得P、C间距离为(海里)
8.解:(1)由余弦定理，(Ⅱ)由，且得由正弦定理，解得。所以。由倍角公式，且，故.9.解:(Ⅰ)由，且，，又，.(Ⅱ)∵,，又
.10.解:(Ⅰ)由题设及正弦定理，有。故。因为钝角，所以。由，可得，得。
(Ⅱ)由余弦定理及条件，有，故。由于△面积，又，当时，两个不等式中等号同时成立，所以△面积的最大值为。暑假作业(三)
一.选择题: A D D
3.解：不妨设ab，则，另一方面，a为最长边，b为最短边。设其夹角为，则由余弦定理可得a2-ab+b2=a2+b2-2abcos，解得cos=，又∵为三角形的内角，=60。故选D。
二.填空题: 4.5.6.6.解:因为锐角△ABC中，A+B+C=，所以cosA=，则，则bc=3。将a=2，cosA=，c=代入余弦定理：中得,解得b=
三.解答题:
7.解:(Ⅰ)由题设及正弦定理，有.故.因为为钝角，所以.由，可得，得，.(Ⅱ)由余弦定理及条件，有，因，所以.故，当时，等号成立.从而，的最大值为.8.证：(1)∵sin(A+B)= , sin(A-B)=...tanA=2tanB.(2)∵
设AB边上的高为CD，则AB=AD+DB=，由AB=3，得CD=2+，AB边上的高等于2+。
9.解: ∵，或，(1)时，;
(2)时。
10.解: ∵A、B、C为△ABC的三内角，,.令,∵A是△ABC的内角 ,当时，为其最大值。此时
暑假作业(四)
一.选择题: D D A
1.解:由得即，又在△中所以B为或.二.填空题: 4.5.6.4.解:由题意，得为锐角，，由正弦定理得 ,.5.解: ,又, 解得.，是锐角..,，.又，.,.6.解：由余弦定理，由，且得由正弦定理，解得
。所以。由倍角公式，且，故.三.解答题:
7.解:(1)由,得，则有 =,得 即.(2)由,推出而,即得，则有 ,解得.8.解:(Ⅰ)由及正弦定理得，,，是锐角三角形,.(Ⅱ)由面积公式得 由余弦定理得21世纪教
由②变形得.解法二：前同解法1，联立①、②得,消去b并整理得
解得.所以,故.21世纪教育网
9.解: 由，,，又，由得, 即，,，由正弦定理得.10.解:()∵,=,且,，即,∵，.由的面积，得
由余弦定理得，又,，即有=4.()由()得，则12=, ,∵,，故的取值范围为.方法二：由正弦定理得,又()得.==,∵，, ,的取值范围为.暑假作业(五)
一.选择题: C C A
二.填空题: 4.或 5.63 6.三.解答题:
7.解:设数列{an｝的公差为d，首项为a1，由已知得 5a1 + 10d =-5, 10a1 + 45d = 15，解得a1=-3，d=1。Sn = n(-3)+，∵{｝是等差数列且首项为=-
3、公差为。
Tn = n(-3)+
8.解:(1)由已知，得.当2时，,所以,由已知，,设等比数列的公比为，由得，所以,所以.(2)设数列的前项和为，则，两式相减得,所以.9.解：(I)由条件又是公差为1的等差数列，=n2(nN*)。
解法二：由即，又
∵是公差为1的等差数列，即，(II)=(1)n，=12+2232++(1)nn2。
① n是偶数时，=(2212)+(4232)++[n2(n1)2]=;
② n是奇数时。
10.解：(Ⅰ)当时，即是等比数列.(Ⅱ)由(Ⅰ)知，若为等比数列，则有而故，解得，再将代入得成立，所以.暑假作业(六)
一.选择题: D D D
1.解：设等比数列的公比为，则有。当时，(当且仅当q=1时取等号);当时，(当且仅当q=-1时取等号)。所以的取值范围是，故选D。
3.解：∵每4个括号有10个数，第104括号中有4个数，第1个为515，和为
515+517+519+521=2072，选D。
二.填空题: 4.5.6.3
4.解：。，将代入成立。
5.解：。
6.解：3 由，可得。
。故填3。
三.解答题:
7.解:(1)an=;(2)an=(-1)n.(3)an=;(4)
(5);(6)an=n+
8.解：∵{an}是等差数列，a2+a4=2a3 ,∵a2+a4=b3,b3=2a3,∵{bn}是等比数列，b2b4=b23 ，∵b2b4=a3 , a3=b23 ,即b3=2b23, ∵b30，b3=,a3=,由a1=1，a3=,公差., 由.当;当.9.解:(Ⅰ)由 得 3anan+1 +an+1 = an ,从而，即,数列是以为首项3为公差的等差数列。
(Ⅱ)设bn = anan+1 ,则 ,，.10.解：(1)由题意，为等差数列，设公差为，由题意得，.(2)若，时。
故。
暑假作业(七)
一.选择题: B C B
1.解：，当时，有;当，有。综上，有，选B。
3.解：易知，且。当时，在时0，故选B。二.填空题: 4.14 5.6.;;
三.解答题:
7.解：(1)设数列共2m+1(mN*)把该数列记为{an｝，依题意a1+a3++a2m+1=44且
a2+a4++a2m=33，即(a2+a2m)=33.(1)(a1+a2m)=44.(2)(1)(2)得.m = 3.代入(1)得a2+a2m = 22，am+1==11 即该数列有7项，中间项为11
方法二: S奇+S偶=Sn;S奇─S偶=a中;Sn=na中 a中=11
(2)(奇数项之和)，两式相除得到：(m+1)/(m─1)=4/3 m=7，再联立方程组解得：a1=20,am=2d=─3an=─3n+23
8.解：(Ⅰ)∵a3，a5是方程的两根，且数列的公差d0，a3=5，a5=9，公差 又当n=1时，有b1=S1=1-
当数列{bn}是等比数列，(Ⅱ)由(Ⅰ)知
9.解：(Ⅰ)由,得，两式相减得，即，又,，, ，数列是首项为，公比为的等比数列 ,.(Ⅱ)由(Ⅰ)知,.(Ⅱ)方法二: 由已知 ① 设，整理得 ②, 由①、②，得.即①等价于,数列是等比数列，首项
为，公比为，.10.解：(1)∵.又.是一个以2为首项，8为公比的等比数列,.(2),.最小正整数.暑假作业(八)
一.选择题: D B A
二.填空题: 4.-4 5.6.5.解：依题意，而，故，根据等比数列性质
知也成等比数列，且公比为，即，.6.解：，。
三.解答题:
7.解：(1)设{an}的公差为d, {bn}的公比为q，则,解得(舍)或.an=1+(n-1)(-2)=3-2n, bn=(-1)n-1.(2)设Sn=a1b1+a2b2+a3b3++anbn,则Sn=a1-a2+a3-a4++(-1)n-1an，当n为偶数时Sn=(-d)=n;当n为奇数时，Sn=Sn-1+(-1)n-1an=(n-1)+an=2-n.方法二：Sn=a1b1+a2b2+a3b3++anbn,，.将q=-1, bk=(-1)k-1, ak=3-2k,(k=1, 2,，n), d=-2，代入整理可得：Sn=1+(n-1)(-1)n.8.解：(1)由题意知：4(an+1-an)(an-1)+(an-1)2=0,(an-1)(4an+1-3an-1)=0.∵a1=2,an-10，即4an+1=3an+1.假设存在常数C，使{an+C}为等比数列，则：为常数.c=-1，故存在常数c=-1，使{an-1}为等比数列.(2), 从而,.9.解：(Ⅰ)当时，当时，.又满足,.∵，数列是以5为首项，为公差的等差数列.(Ⅱ)由已知，∵，又，数列是以为首项，为公比的等比数列.数列前项和为.10.解：(Ⅰ)
(Ⅱ)∵
猜想：是公比为的等比数列.证明如下：
∵，是首项为的等比数列.暑假作业(九)
一.选择题: A C D
二.填空题: 4.7 5.6.1
4.解：据题意，有，故前7项为正数。
5.解：。
三.解答题:
7.解：(1)由已知有，解得，所以。
当时，(2)令，则，当时。。
8.解：设等差数列的公差为，前n项和为，则，是等差数列。
解法二：设的前n项和为，是等差数列。
9.解：(I)设等差数列的公差为d.由即d=1.所以即
(II)∵，10.解：(Ⅰ)由 得
即
∵，解得，(Ⅱ)∵是首项、公比的等比数列，故则数列的前
前两式相减，得，即
暑假作业(十)
一.选择题: C A B
二.填空题: 4.5.6.三.解答题:
n项和
7.解：(Ⅰ)由题设
(Ⅱ)若当 故
若当
故对于
8.解：(1)设是公差为d，的公比为q，则依题意有q0且
解之得。
(2)∵，,① ,② ②-①得:.9.解：(1)斜率为1，纵截距为2的直线方程为： 即是以2为公差，2为首项的等差数列，(2)，于是，即为递增数列，的最小项为
10.解：(1)设第一年的森林的木材存量为，第年后的森林的木材存量为，则，，.(2)当时，有得即，.即经过8年后该地区就开始水土流失.暑假作业(十一)
一.选择题: A C C
二.填空题: 4.512 5.24 6.三.解答题:
7.解：设这四个数为：，则，解得：或，所以所求的四个数为：;或.8.解：(1)当n=1时，当，是以2为公比，4为首项的等比数列。
(2)，是以1为首项，1为公差的等差数列。
(3)，两式相减得：。，即的前n项和为：。
9.解：(1)由整理得.又，所以是首项为，公比为的等比数列，得
(2)由(1)可知，故.则
又由(1)知且，故，因此为正整数.10.解：(Ⅰ)=3，=6.由0，0，得03，又，=1，或=2.当=1，02时，共有2个格点;当=2，0时，共有个格点.故.(Ⅱ)由(1)知=，则-=.当3时，.又=9==，所以，故.总结：以上就是高一数学暑假作业答案的全部内容，希望同学们在做题的过程中养成不断总结的好习惯，考试中避免出现技术性错误，在高中取得最好的成绩!
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